The amount of heat needed to raise 25 g of a substance by 15°c is 293 j. what is the specific heat of the substance? use the equation c = q/mδt. a.) 0.13 j/g-°c b.) 0.20 j/g-°c c.) 0.78 j/g-°c d.) 0.46 j/g-°c

It is so simple and direct substitution in the formula of :
C= Q/ m ΔT
when C is specific heat constant
and Q is heat energy of joul 
and m is the mass
and ΔT is the change in temperature
and when we have Q = 293 J & m = 25 g & ΔT = 15 °C so by substitution:
∴C = 293/(25*15)
      = 0.78 J/g-°C 
∴ 0.78 J/g-°C is the correct answer