The reaction of 0.779 g k with o2 forms 1.417 g potassium superoxide, a substance used in self-contained breathing devices. determine the formula for potassium superoxide.

First we need to find the number of moles of both K and O reacted
K - 0.779 g / 39 g/mol
  = 0.02 mol
the mass of O₂ reacted = 1.417 g - 0.779 g = 0.638 g
O₂ moles = 0.638 g / 32 g/mol
               = 0.02 mol 
the number of both K and O₂ moles reacted are equal 
therefore stoichiometry of K to O₂ reacted are 1:1 
then the formula of potassium superoxide is KO₂

Is there a diagram/picture you can provide? it seems this question goes along with a