What volume of 6.00 m naoh would be required to increase the ph to 4.93?

The Volume of  NaOH is mathematically given as

V=3.2 L

Generally the formula for PH is

Ph= Pka + log[A^-]/[HA]

4.93 = 4.76 + log((40+X)/(60-X))

0.17 = log ((40+X)/(60-X))

Therefore

X= 19.66 mmol = 0.019 mol

Generally the formula for molarity is

M= number of moles / volume    

6 = 0.019 / V

V=3.2 L

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