If 23 g of sodium reacts completely with 71 g of chlorine, grams of product would be expected. round your answer to the nearest gram. what would be the answer?

2 Na + Cl2 ==> NaCl

The equation of reaction needs 1 Na atom and 1 Cl atom for reactant to create 1 NaCl. You need to determine which reactant will be used up.
Natrium molecular weight is 23g/mol so the natrium you have is: 23g/ (23g/mol)= 1 mol.
Chlorine molecular weight is 35.5g/mol, so the chlorine you have is: 71g/ (35.5g/mol)= 2 mol.

The reaction will use 1 mol of natrium and 1 mol of chlorine to produce 1 mol of NaCl. The weight would be: 23g + 35.5g= 58.5 grams

It could possibly be beneficial if the experiment is successful.