At a certain temperature, the equilibrium constant, kc, for this reaction is 53.3. at this temperature, 0.500 mol of h2 and 0.500 mol of i2 were placed in a 1.00-l container to react. what concentration of hi is present at equilibrium? equation: h2 + i2 = 2hi

When the balanced equation for the reaction is:
           H2(g) + i2(g)⇄ 2Hi
initial    0.5      0.5        X
             -X        -X         +X
Final (0.5-x)    (0.5-x)   2X

by substitution at the Kc formula:
Kc= [Hi]^2 / [H2] * [i2]
53.3 = (2X)^2 / (0.5-X) (0.5-X)by taking the square route
√53.3 = 2X / (0.5-X)
∴X = 0.39 m
∴[Hi] = 0.39 m