N2 + 3 h2 -> 2 nh3 how many mols of n2 will be produced if it reacts with 2.5 x 1021 molecules of n2

N2 + 3H2 = 2NH3 

First, we need to determine the number of N2 moles:

n(N2)=N/NA=2.5 x 10²¹ / 6x10²³ = 0.0042 mole

According to the equation of the reaction of ethane combustion, nitrogen and ammonia have following stoichiometric ratio:

n(N2) : n(NH3) = 1 : 2

n(NH3) = 2xn(N2)

n(NH3) = 2x0.0042 = 0.0083 mole of NH3 will be produced in the reaction

What do you mean by that? like the contents? the thc level?