Question 8 4 pts what would be the resulting molarity of a solution made by dissolving 31.3 grams of ca(oh)2 in enough water to make a 1050-milliliter solution? show all of the work needed to solve this problem.

Answer : The molarity of the solution is, 0.4028 mole/L

Explanation : Given,

Mass of = 31.3 g

Molar mass of = 74 g/mole

Volume of solution = 1050 ml

Molarity : It is defined as the moles of solute present in one liter of solution.

Formula used :

Now put all the given values in this formula, we get:

Therefore, the molarity of the solution is, 0.4028 mole/L