Carbonyl fluoride, cof2, is an important intermediate used in the production of fluorine-containing compounds. for instance, it is used to make the refrigerant carbon tetrafluoride, cf4 via the reaction 2cof2(g)⇌co2(g)+cf4(g), kc=8.90 if only cof2 is present initially at a concentration of 2.00 m, what concentration of cof2 remains at equilibrium?

0.32 m

Explanation:

                     2 COF2   CO2 + CF4 ( all gases)

initially                  2                        0          0

equilibrium           2-x                     x          x

Then the equilibrium constant given by the coefficients in the balanced equation is:

K =    x * x /( 2-x)  = 8.90

Then  x^2/(2-x) = 8.90

It gets a bit messy since we get to solve  a  quadratic equation :

       x^2 = 17.80 - 8.90 x

       x^2 + 8.90 x - 17.80 = 0

After solving we get that x is equal to 1.68

Therefore the amount of COF2 at equilibrium is ( 2 - 1.68 ) m or

0.32 m

Note: We can check answer by plugging the results in the equilibrium equation.

do u have any choices to choose from ? ?

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.