The r-cooh compound behaves as an acid base alcohol ester

Option (a) is the correct answer.

Explanation:

An organic compound that contains "-COOH" as the function group is known as carboxylic compound.

A carboxylic compound is an acid as it dissociates to give hydrogen ion.

Whereas a compound with functional group "-OH" is known as alcohol.

And, a compound with general formula RCOOR' is known as an ester.

Thus, we can conclude that the R-COOH compound behaves as an acid.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j