Chemistry, 31.07.2019 18:00 pankajyadav7402

If a laboratory analysis of the mineral aegirine yields 10.0% na, 24.2% fe, 24.3% si, and 41.5% o, what is the empirical formula of the compound?

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When determining empirical formulas the percentages are first divided by their respective molar masses
Na (23 g/mol) Fe (56 g/mol) Si (28 g/mol) O (16 g/mol)
10.0 24.2% 24.3% 41.5 %
10.0/23 24.2/56 24.3/28 41.5/16
=0.43 =0.43 = 0.86 =2.59
divide all these values by the lowest fraction which is 0.43
0.43/0.43 0.43/0.43 0.86/0.43 2.59/0.43
=1 =1 =2 =6.02
When we round off these values the ratio of Na:Fe:Si:O = 1:2:6
therefore empirical formula would be NaFeSi2O6

Answer from: lulu8167

To make it easier, assume that we have a total of 100 g of aegirine. Hence, we have 10g of Na, 24.2g of Fe, 24.3g of Si and 41.5g of O. Know we will convert each of these masses to moles by using the atomic masses of Na, Fe, Si, and O:

$\frac{10g Na}{23g/mole} = 0.43 mole Na$

$( \frac{24.2g Fe}{55.9g/mole} ) = 0.43 mole Fe$

$( \frac{24.3g Si}{28.1g/mole} ) = 0.86 mole Si$

$( \frac{41.5g O}{16g/mole} ) = 2.59 mole O$

Now, we will divide all the mole numbers by the smallest among them and get the number of atoms in the mineral:

Na = 0.43/0.43 = 1

Fe = 0.43/0.43 = 1

Si = 0.86/0.43 = 2

O = 2.59/0.43 = 6

So, the empirical formula of the compound NaFeSi2O6

Answer from: Quest

the correct name for the n3 ion is azide. azide is a polyatomic anion with a -1 charge and is written as n3 -1. it consists of three nitrogen atoms bonded together. hope i . let me know if you need anything else.

Answer from: Quest

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.

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If a laboratory analysis of the mineral aegirine yields 10.0% na, 24.2% fe, 24.3% si, and 41.5% o, w...