Titration #1 a total of 25.0 ml of 0.150 m potassium hydroxide (koh) was required to neutralize 15.0 ml of sulfuric acid (h2so4) of unknown concentration. what is the concentration of the sulfuric acid? balanced equation: acid(unknown) - solution, molar ratio, volume, concentration base(known) - solution, molar ratio, volume, concentration

2KOH + H2SO4 = K2SO4 + 2H20

From the reaction, it can be seen that KOH and H2SO4 have the following amount of substance relationship:

n(KOH):n(H2SO4)=2:1

From the relationship we can determinate required moles of H2SO4:

n(KOH)=c*V=0.15M*0.025L= 0.00375 mole 

So,

n(H2SO4)=n(KOH)/2= 0.00375/2= 0.00188 moles

Now, when moles of H2SO4 is known, concentration can be calculated: 

c(H2SO4)=n/V= 0.00188mole/0.015L= 0.125M

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