In the reaction below, hydrogen peroxide decomposes to water. mm h2o2 = 34.02 g/mol mm h2o = 18.02 g/mol mm o2 = 32 g/mol 2h2o2 → 2h2o + o2 if 14.3 moles of h2o2 is decomposed, how many grams of oxygen gas are produced? show all your work to get full credit.

228.8 g of O2 are produced

Explanation:

1) Balanced chemical equation:

Given

2H2O2 → 2H2O + O2

2) mole ratios

2 mol H2O2 : 2 mol H2O :1 mol O2

3) proportion with the unknown quantity of O2:

          x                      1 mol O2
=
 14.3 mol H2O2        2 mol H2O2

4) Solve for x:

x = 14.3 mol H2O2 * 1 mol O2 / 2 mol H2O2 = 7.15 mol O2

5) Convert 7.15 mol O2 to grams

molar mass = mass in grams / number of moles

=> mass in grams = number of moles * molar mass

molar mass of O2 = 2 * 16.00 g/mol = 32.00 g/mol

mass in grams O2 = 7.15 moles * 32.00 g / mol = 228.8 g

228.8 g

Both models are effective because they show the valence electrons, and these valence electrons indicate the reactivity of an element.