Asample of cyanic acid, hcn, contains 3.33x10^22 atoms. how many moles of cyanic acid are in the sample? **hint, find the number of molecules of hcn first**

1mole of any compound has 6.02 x 10^23 molecules
for hcn it has 3 molecules therefore (3.33 x 10^22)/3 = 1.11 x 10 ^22
so (1.11 x 10^22)/(6.02 x 10^23) = 0.0184 moles of cyanic acid are present in the sample.

Ifound this on google “these two compounds have a different ionic structure. caesium ion is larger in size when compared to the sodium ion. the charge gets more area to spread out evenly. so caesium chloride has a lower melting point than sodium chloride.” i hope this you for what your looking for