In the chemical reaction: br2(g) + cl2(g) ↔ 2 brcl(g) kp = 0.150 if there is initially 0.500 atm of brcl and nothing else in a container, what direction does the reaction move: a) q > k and the reaction moves to the right b) q > k and the reaction moves to the left c) q < k and the reaction moves to the left d) q < k and the reaction moves to the right

We know that

Kp = Product of partial pressures of products / product of partial pressures of reactants

For given reaction

Br2(g) + Cl2(g) ↔ 2 BrCl(g)

Q = p^2BrCl / pBr2 X pCl2   [Q= reaction quotient]

now as given that there is only BrCl in the container so the pressure of BrCl will be only pressure to be accounted

Hence

Q= (0.5)^2 = 0.25

Now as Q > Kc The reaction will move in backward direction or left side or reactant side s

so answer is

Q > K and the reaction moves to the left

the child will have heterozygous dominant chromosomes as characters of his father are dominant over the characters of his mother.

the child is heterozygous

what is the question here. i think you messed up.