The reaction described in part a required 3.65 l of sodium chloride. what is the concentration of this sodium chloride solution?

Chemical reaction: AgNO₃ + NaCl → AgCl + NaNO₃.
Missing question: Part A:What mass of silver chloride can be produced from 1.40 L of a 0.180 M solution of silver nitrate? 
V(AgNO₃) = 1,4 L.
c(AgNO₃) = 0,180 M = 0,180 mol/L.
V(NaCl) = 3,65 L.
n(AgNO₃) = V(AgNO₃) · c(AgNO₃).
n(AgNO₃) = 1,4 L · 0,180 mol/L.
n(AgNO₃) = 0,252 mol.
From chemical reaction: n(AgNO₃) : n(NaCl) = 1 : 1.
n(NaCl) = 0,252 mol.
c(NaCl) = 0,252 mol ÷ 3,65 L.
c(NaCl) = 0,069 mol/L

The answer is the first option just took the test