When 11 g h2(g) and 37.25 g co(g) are combined, how many grams of methyl alcohol are produced?

Hydrogen  react  with  with   carbon  monoxide(Carbon  (ii)  oxide)  to   form   methyl  alcohol
  CO  +  2H2  >  CH3OH
step  one  calculate  the  number  of  moles  of  H2

=  11g/2.0 g/mol (molar mass  of  H2  moles  =  5.5moles
  calculate  the  moles   CO  =   37.25grams/28  =1.330moles
 The  reacting  ratio  of  of  H2  to  CH3OH   2:1
1.330 x 2/1+2.661  moles  of  H2  but  there  is  more  H2  present  than  that  of  co
therefore  the  grams  of  CH3OH  is  threfore  =1.330  x32(molar  mass  of  CH3OH) =42.65grams

1. and 2. question: in which equation? or i don't understand you, 3. a), 4. c), 5. c), 6. b), 7. d), 8. d) if small number is underlined(behind symbol) , b) if big number is underlined(in front of symbol)9. what is underlined there? 10. c)