How much heat is produced by combustion of 125 g of methanol under standard state conditions?

Energy released = 2832.79 kJ

Explanation:

The standard enthalpy of the combustion of methanol,

It means that :

1 mole of methanol on combustion releases 726.1 kJ of energy

Molar mass of methanol = 32.04 g/mol

Thus, mass of 1 mole of methanol is 32.04 g

So,

32.04 g of methanol on combustion releases 726.1 kJ of energy

1 g of methanol on combustion releases 726.1/32.04 kJ of energy

125 g of methanol on combustion releases (726.1/32.04)*125 kJ of energy

Energy released = 2832.79 kJ

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.

they are both synthetic elements

explanation:

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