Consider the chemical equation. 2h2 + o2 mc022-1.jpg 2h2o what is the percent yield of h2o if 87.0 g of h2o is produced by combining 95.0 g of o2 and 11.0 g of h2? use mc022-2.jpg.

Answer :  The percent yield of is, 87.88%

Solution :

First we have to calculate the moles of and .

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 2 moles of react with 1 mole of

So, 5.5 moles of react with moles of

That means, in the given balanced reaction, is a limiting reagent because it limits the formation of products and is an excess reagent.

The excess reagent remains  = 2.9 - 2.75 = 0.15 moles

Now we have to calculate the moles of .

As, 2 moles of react with 2 moles of

As, 5.5 moles of react with 5.5 moles of

Now we have to calculate the mass of .

Therefore, the mass water produces, 99 g

Now we have to calculate the percent yield of .

Therefore, the percent yield of is, 87.88%

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