How many atoms are present in 179.0 g of iridium?

Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units/mole. This number can be used to convert the number of atoms or molecules into a number of moles. We do as follows:
 179.0 g of iridium (1 mol / 192.217 g) ( 6.022 x 10^23 atoms /  1 mol ) = 5.61 x 10^23 atoms of iridium 
Hope this answers the question.

The metal is named first

Ithink that’s it’s b