A1.543 gram sample containing sulfate ion was treated with barium chloride reagent, and 0.2243 grams of barium sulfate was isolated. calculate the percentage of sulfate ion in the sample.

The mass percent of sulfate ion in the sample is 5.98 %

Explanation:

We are given:

Mass of barium sulfate = 0.2243 g

We know that:

Molar mass of barium sulfate = 233.4 g/mol

Molar mass of sulfate = 96.06 g/mol

To calculate the mass of sulfate ion present in given amount of barium sulfate, we use unitary method:

In 233.4 g of barium sulfate, the mass of sulfate ion present is 96.06 g

So, in 0.2243 g of barium sulfate, the mass of sulfate ion present will be =

To calculate mass of sulfate ion present in the sample, we use the equation:

Mass of sulfate ion = 0.0923 g

Mass of sample = 1.543 g

Putting values in above equation, we get:

Hence, the mass percent of sulfate ion in the sample is 5.98 %

the best answer is d because the strong cohesion is caused by the ability of water molecules to undergo hydrogen bonding.

a is incorrect because when water solidifies, it becomes   ice, which expands and occupies a bigger volume for the same mass of water in its liquid state.

b is incorrect because water has high surface tension. besides bonding to itself it hydrogen bonds to other molecules at the top decreasing possibility for breaking of attractive forces.

c is incorrect because the water molecule has oxygen which is highly electronegative and so pulls the electron pair towards itself creating a dipole moment, making the molecule polar.

e is incorrect because water has strong adhesion, ability to stick to other molecules such as glass because of this molecules having stronger hydrogen bonding than water.