What is the empirical formula of a compound consisting of 29.6% oxygen and 70.4% fluorine by mass?

Answer : The empirical formula of the compound is,

Solution : Given,

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of O = 29.6 g

Mass of F = 70.4 g

Molar mass of F = 19 g/mole

Molar mass of O = 16 g/mole

Step 1 : convert given masses into moles.

Moles of O =

Moles of F =

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For O =

For F =

The ratio of O : F = 1 : 2

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula =

Therefore, the empirical formula of the compound is,

answer is: nuclear fusion produces elements that are heavier than helium.

nuclei combine to form a heavier nucleus, releasing energy.  

for example, fusion of hydrogen atoms at the sun.  

this fusion nuclear reaction is in the inner core of the sun and hydrogen (atomic number 1) is conveted into helium (atomic number 2).  

the inner core is the central region of the sun and all solar energy is produced in the core by nuclear fusion.