Helium in a toy balloon does work on its surround- ings as it expands with a constant pressure of 2.52 × 105 pa in excess of atmospheric pressure. the balloon's initial volume is 1.1 × 10−4 m3, and its final volume is 1.50 × 10−3 m3. determine the amount of work done by the gas in the balloon.

Work is calculated as P*(V2 - V1). In this problem, we have a constant P = 2.52 x 10^5 Pa, an initial volume V1 = 1.1 x 10^-4 m^3, and a final volume V2 = 1.50 x 10^-3 m^3.
Substituting:
P*(V2 - V1)
= (2.52 x 10^5 Pa)(1.50 x 10^-3 - 1.1 x 10^-4) m^3
= 350.28 Pa-m^3
= 350.28 J
So the gas in the balloon does 350.28 J of work on its surroundings.

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