Metallic copper is formed when aluminum reacts with copper(ii) sulfate. how many grams of metallic copper can be obtained when 54.0 g of al react with 319 g of cuso4? 2al + 3cuso4 → al2(so4)3 + 3cu

Answer is: 127 grams of metallic copper
Chemical reaction: 2Al + 3CuSO₄ → Al₂(SO₄)₃ + 3Cu.
m(Al) = 54 g.
m(CuSO₄) = 319 g.
m(Cu) = ?
n(Al) = 54 g ÷ 27 g/mol
n(Al) = 2 mol.
n(CuSO₄) = 319 g ÷159,5 g/mol.
n(CuSO₄) = 2 mol, limiting reagens.
from reaction n(CuSO₄) : n(Cu) = 3 : 3 (1 : 1).
n(Cu) = 2 mol.
m(Cu) = 2 mol · 63,5 g/mol.
m(Cu) = 127 g.

Idon't know hope someone you

Use a magnet to separate iron, evaporate water, i'm not sure how to separate the other two i'm sorry but good luck