One of the reactions for rusting iron is as follows: 4fe + 3o2 → 2fe2o3 (mm fe: 55.85 g/mol; mm o2=32 g/mol; mm fe2o3=159.70 g/mol) if 63.98 g of oxygen gas is completely consumed, how many moles of iron (iii) oxide are formed? a. 1.333 mol b. 3071 mol c. 2.999 mol d. 6812 mol

A. 1.333 mol

Explanation:

To calculate the moles, we use the equation:

As oxygen is completely consumed, it is the limiting reagent and will limit the formation of .

According to stochiometry,

3 mole of produces 2 moles of

Thus 2 moles of will produce= moles of

Thus the correct answer is 1.333 moles

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hope it ,

bioteacher101