For the haber process, n2 + 3h2 → 2nh3, what volume of nitrogen is consumed at stp if you collect 44.8 l of ammonia in excess hydrogen (n = 14 amu, h = 1 amu)?

Answer is: 22,4 l of nitrogen.
Chemical reaction: 3H₂ + N₂ ⇄ 2NH₃.
V(NH₃) = 44,8 l = 44,8 dm³.
V(N₂) = ?
n(NH₃) = V(NH₃) ÷ Vm
n(NH₃) = 44,8 dm³ ÷ 22,4 dm³/mol
n(NH₃) = 2 mol.
from reaction: n(N₂) : n(NH₃) = 1 : 2
n(N₂) : 2 mol = 1 : 2
n(N₂) = 1 mol.
V(N₂) = n(N₂) · Vm
V(N₂) = 1 mol · 22,4 dm³/mol = 22,4 dm³.
Vm - molar volume

What does that mean you dum bum

What do you mean by that? like the contents? the thc level?