Which quantity is equivalent to 39 grams of lif?

This question is incomplete, the completed question is below.

(a) 1.0 mole  

(b) 2.0 mole  

(c) 0.50 mole

(d) 1.5 mole

The correct option is d

Explanation:

LiF is Lithium flouride. Lithium (Li) has a molar mass of 7 g/mol while flourine (F) has a molar mass of 19 g/mol. Hence, 1 mole of LiF will be

7 + 19 = 26 g/mol

If 1 mole of LiF = 26g,

X mole of LiF = 39g

When you cross multiply, you will have

X mole x 26g = 1 mole x 39g

make X the subject and you will have

X mole = 1 mole x 39g/26g

X mole = 1.5 mole

Hence, 1.5 mole of LiF is equivalent to 39 grams of LiF

the correct answer is:

a. formation of precipitation