If you have 25.0 ml of a 6.50m naoh solution and you add 10.0 ml of water to it, what is the new concentration?

Explanation:

The given data is as follows.

        = 25.0 ml,       = (10.0 ml + 25.0 ml) = 35.0 ml

        = 6.50 M,        

Relation between volume and molarity of the two liquids is as follows.

        =

        =    

              = 4.64 M

Thus, we can conclude that new concentration is 4.64 M.

it would be a gas formation

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.