The combustion of ammonia in the presence of excess oxygen yields no2 and h2o: 4 nh3 (g) + 7 o2 (g) â 4 no2 (g) + 6 h2o (g) the combustion of 28.8 g of ammonia consumes g of oxygen.

The answer would be 118.68 g.
Explanation for this is:4 moles of NH3 give 4 moles of NO2 
so 1mole of NH3 will give 1 mole of NO2 
43.9 grams of NH3 contains 2.58 moles 
so 2.58 moles will be produced of NO2 
which is 118.7 grams this the amount of oxygen that is used.

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