Consider the balanced equation.  pcl3 + 3h2o h3po3 + 3hcl                             what is the percent yield of hcl if 42.0 g of hcl are produced from the reaction of 62.0 g of pcl3? a. 28.4% b. 72.8% c. 85.0% d. 93.5% plz

Given:

PCl3 + 3H2O → H3PO3 + 3HCl

Mass of HCl = 42.9 g

Mass of PCl3 = 62.0 g

To determine:

% yield of HCl

Explanation:

Molar mass of PCl3 = 137 g/mol

# moles of PCl3 reacted = mass/molar mass = 62 g/137 g.mol-1 = 0.453 moles

Based on the reaction stoichiometry:

1 mole of PCl3 produces 3 moles of HCl

therefore, 0.453 moles of PCl3 would be expected to produce: 0.453 * 3 = 1.359 moles of HCl

Molar mass of HCl = 36 g/mol

Therefore, expected mass (theoretical yield) of HCl = # moles of HCl * molar mass

 = 1.359*36 = 48.92 g

% yield = (actual yield/theoretical yield)*100

% yield of HCl= (42.0/48.92)*100 = 85.9 %

Ans: (C)

explanation: