Is mass conserved when 40 g of sodium hydroxide undergoes a chemical change during an interaction with 36.5 g of hydrogen chloride? use complete sentences to support your answer by explaining how this can be demonstrated.

Given information:

Mass of sodium, NaOH = 40 g

Mass of HCl = 36.5 g

To determine:

If mass is conserved when NaOH reacts with HCl

Explanation:

Based on the law of conservation of mass, for any chemical reaction, the total mass of the reactants is equal to the total mass of the products

Here we have:

NaOH + HCl → NaCl + H2O

The reactants and products are present in a 1:1 ratio

Mass of Reactants:                          Mass of Products:

NaOH = 40 g                                     NaCl = 23 + 35.5 = 58.5 g

HCl = 36.5 g                                      H2O = 2(1) + 16 = 18 g

Total mass = 40 + 36.5 = 76.5 g       Total mass = 58.5 + 18 = 76.5 g

Ans:  mass of reactants = mass of products = 76.5 g. Hence, mass is conserved.

answer

the ions in solute supperate from eachouthere

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).