The following equation is one way to prepare oxygen in a lab. 2kclo3 → 2kcl + 3o2 molar mass info: mm o2 = 32 g/mol mm kcl = 74.55 g/mol mm kclo3 = 122.55 g/mol if 4.00 moles of kclo3 are totally consumed, how many grams of oxygen gas would be produced? 192 g 6.00 g 85.3 g 735 g

Explanation:

Following the reaction, for each 2 moles of KClO3 consumed completely, 3 moles of oxygen are generated.

So, if 4 moles are consumed:

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.

its first and third is your answer i did the qustion the fourth isnt right