Aparticular yeast ferments glucose (c6h12o6; molar mass = 180.2 g/mol) and generates ethanol (c2h5oh; molar mass = 46.07 g/mol) with an 87% yield. what mass of glucose is required to produce 475 g of ethanol by this process?

First, you have to write down the equation from glucose, C₆H₁₂O₆, to ethanol, C₂H₅OH.

C₆H₁₂O₆ --> 2 C₂H₅OH + CO₂

So, the ratio for glucose to ethanol is 1:2. The solution is as follows:

Mass of glucose required = (475 g)(0.87)(1mol/46.07 g ethanol)(1mol gluose/2 mol ethanol)(180.2 g/mol glucose)
Mass of glucose required = 808.2 g

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.