How many milliliters of 0.755 m h2so4 solution is needed to react with 55.0 ml of 2.50 m koh solution? given: 2 koh (aq) + h2so4 (aq) → 2 h2o (l) + k2so4 (aq)?

KOH  (2.50 mol/L) (0.0550 L) = 0.1375 mol  

The KOH to H2SO4 molar ratio of 2 to 1 is the key. Only H2SO4 neutralized KOH

0.1375 mol / 2 = 0.06875 mol  H2SO4 amount  

volume required of H2SO4 ---> 0.06875 mol / 0.755 mol/L = 0.0910596 L = 91.0 mL

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

16

explanation:

the marks go by 4s