A52.8-g sample of glucose (a nondissociated, nonvolatile solute with the formula c6h12o6) is dissolved in 158.0 g of water. what is the vapor pressure of this solution at 100°c?

Calculate  the  mole  of  glucose  and  water
 The  moles  of water =158g/18g/mol=8.778 moles
moles of  glucose =52.8g/180g/mol=0.293 moles
determine  the mole  fraction  of  the  solvent
that  is   x solvent = 8.778/ (8.778+0.293)=0.9677
use  the  Raults  law  to  determine  the  vapor  pressure
100  degree  of  water  has   a  vapor  pressure  of  760 mmhg
p solution=(x  solvent) (p^o solvent)
p solution=0.9677 x760 =735.45 mmHg

Less stable  hope this