Calculate the molarity of a solution made by putting 55.8 g of nano3 into a beaker and diluting to 2.50 l.

Answer : The molarity of a solution is 0.263 mole/L.

Solution : Given,

Mass of = 55.8 g

Volume of solution = 2.50 L

Molar mass of = 84.99 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula used :

where,

w = mass of solute

M = molar mass of solute

V = volume of solution

Now put all the given values in above formula of molarity, we get

Therefore, the molarity of a solution is 0.263 mole/L.

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