When 90 g of water is split by electrolysis (2h2o → 2h2 +o2) at stp, how many liters of oxygen gas will be collected? question 6 options: 44.8 l 22.4 l 56.0 l 67.2 l

2H2O -> 2H2 + O2
Stoichiometric ratio:
2 : 2 : 1

H2O : O2
2 : 1

Mass of 1 mol of H2O = [(2 x 1) + 16] g = 18g

18g of H2O = 1 mol of H2O
90g of H2O = 90g x 1 mol / 18g
= 5 mol of H2O

2 mol of H2O : 1 mol of O2
5 mol of H2O : 5/2 mol of O2

1 mol of O2 = 22.4 L of O2
5/2 mol of O2 = 5/2 mol x 22.4 L / 1 mol
= 56 L of O2