Asample of a hydrocarbon contains 20.75 g c and 4.25 g h. its molar mass is 58.04 g/mol. what is its empirical formula c2h5 ch2 ch c5h

Answer : The empirical formula is,

Solution : Given,

Mass of C = 20.75 g

Mass of H = 4.25 g

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Step 1 : convert given masses into moles.

Moles of C =

Moles of H =

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =

For H =

The ratio of C : H = 1 : 2.5

In the whole number the ratio of C : H = 2 : 5

The mole ratio of the element is represented by subscripts in empirical formula.

Therefore, the empirical formula is,

the term hydride is commonly named after binary compounds that hydrogen forms with other elements of the periodic table. hydride compounds in general form with almost any element, except a few noble gases. the trends and properties vary according to the type of intermolecular force that bonds the elements together, the temperature, its molecular masses, and other components. hydrides are classified into three major groups, depending on what elements the hydrogen bonds to. the three major groups are covalent, ionic, and metallic hydrides. formally, hydride is known as the negative ion of a hydrogen, h-, also called a hydride ion. because of this negative charge, hydrides have reducing, or basic properties. its special characteristics will be further discussed.

explanation: