What will be the freezing point of a solution made by dissolving 5.25 g of naphthalene (c10h8) in 100.0 g benzene ( the normal freezing point of benzene is 5.5°c and k f (benzene) is 5.12°c / m?

1). Calculate the moles of urea you have. Calculate the moles of water you have (150 mL of water = 150 g). Divide moles of water / (moles of water + moles of urea) 2) Molarity is moles of solute / kg of solvent. Calculate the moles of naphthalene in 5.25 g. Divide by the mass of water, 0.1 kg, that is the molality. Multiply by 5.12 deg C / m and subtract from 5.5 C 3) Calculate the mole fraction of water using the method in the first question. Multiply by the vapor pressure of pure water. 1). 0.932 2). 3.4 3). 31.20

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