Me now asap now, find the concentration of h+ ions to oh– ions listed in table b of your student guide for a solution at a ph = 11. then divide the h+ concentration by the oh– concentration. record these concentrations and ratio in table c. what is the concentration of h+ ions at a ph = 11? mol/l  what is the concentration of oh– ions at a ph = 11? mol/l   what is the ratio of h+ ions to oh– ions at a ph = 11? : 1, or 1:

0.00000000001

0.001

0.00000001

100,000,000

Explanation:i am big brain

0.00000000001

0.001

0.00000001:100,000,000

Explanation:

i just did it on edge

the atomic mass is the bottom number on the element.

-steel jelly

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"