Chemistry, 21.07.2019 14:20 meaganblatcher

If 60.2 grams of hg combines completely with 24.0 grams of br to form a compound what is the percent

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Answer from: XAINEE

Answer is: the percent composition of Hg in the compound is 71.5%.

Balanced chemical reaction: Hg + Br₂ → HgBr₂.

m(Hg) = 60.2 g; mass of the mercury.

m(Br₂) = 24.0; mass of the bromine.

m(HgBr₂) = m(Hg) + m(Br₂).

m(HgBr₂) = 60.2 g + 24 g.

m(HgBr₂) = 84.2 g; mass of the compound.

ω(Hg) = m(Hg) ÷ m(HgBr₂) · 100%.

ω(Hg) = 60.2 g ÷ 84.2 g · 100%.

ω(Hg) = 71.5%.

Answer from: VamPL

The percentage composition of Hg in the given compound is $\boxed{71.5{\text{ \% }}}$ .

Further explanation:

The amount of substance that is present in any mixture is known as concentration. It is expressed in different forms, called as concentration terms. Most of the commonly used concentration terms are as follows:

1. Molality

2. Mole fraction

3. Molarity

4. Parts per million

5. Mass percent

6. Volume percent

7. Percentage composition

The given reaction occurs as follows:

${\text{Hg}} + {\text{B}}{{\text{r}}_2} \to {\text{HgB}}{{\text{r}}_{\text{2}}}$

The formula to calculate the percentage composition of Hg is as follows:

${\text{Percentage composition of Hg}} = \left( {\dfrac{{{\text{Mass of Hg}}}}{{{\text{Mass of HgB}}{{\text{r}}_2}}}} \right){\text{100 \% }}$ …… (1)

The formula to calculate the mass of ${\text{HgB}}{{\text{r}}_{\text{2}}}$ is as follows:

${\text{Mass of HgB}}{{\text{r}}_{\text{2}}} = {\text{Mass of Hg}} + {\text{Mass of B}}{{\text{r}}_{\text{2}}}$ …… (2)

The mass of Hg is 60.2 g.

The mass of ${\text{B}}{{\text{r}}_{\text{2}}}$ is 24 g.

Substitute these values in equation (2).

$\begin{aligned}{\text{Mass of HgB}}{{\text{r}}_{\text{2}}} &= 60.2{\text{ g}} + {\text{24 gAC}}\\&= {\text{84}}{\text{.2 g}}\\\end{aligned}$

The mass of Hg is 60.2 g.

The mass of ${\text{HgB}}{{\text{r}}_{\text{2}}}$ is 84.2 g.

Substitute these values in equation (1).

$\begin{aligned}{\text{Percentage composition of Hg}} &= \left( {\frac{{{\text{60}}{\text{.2 g}}}}{{{\text{84}}{\text{.2 g}}}}} \right){\text{100 \% }}\\&= {\text{71}}{\text{.49 \% }}\\&\approx {\text{71}}{\text{.5 \% }}\\\end{aligned}$

Therefore the percentage composition of Hg in the compound is 71.5 %.

Learn more:

Calculate the moles of chlorine in 8 moles of carbon tetrachloride: What is the concentration of alcohol in terms of molarity?

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Concentration terms

Keywords: Hg, Br2, HgBr2, 60.2 g, 24 g, 84.2 g, mass of Hg, mass of Br2, mass of HgBr2, 71.5 %, concentration terms, molality, molarity, mole fraction, percentage composition.

Answer from: Quest

i do not get it at all

Answer from: Quest

substituting a hydrogen atom with a halogen in a hydrocarbon:

- the single bond remains single. a is wrong.

- the bond with hydrogen is as strong as with a halogen. c is wrong

- a hydrocarbon is saturated if there is no double bond. we do not know that so d is wrong.

- carbon will always have four valence electrons. e is wrong.

by elimination, the correct answer is b. the boiling point of the new compound increases.

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If 60.2 grams of hg combines completely with 24.0 grams of br to form a compound what is the percent...

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