The henry's law constant (k) for carbon monoxide in water at 25°c is 9.71 × 10-4 mol/(l·atm). how many grams of co will dissolve in 1.00 l of water if the partial pressure of co is 2.75 atm?

In this question, you are given the Henry constant (9.71 × 10-4 mol/l atm), the volume(1 l) and the pressure(2.75 atm). The molecular mass of CO should be 28g/mol.
Then the amount of carbon monoxide in the water in grams should be: 9.71 × 10-4 mol/l atm * 1l  * 2.75atm * 28g/mol= 747.67 *10^-4= 0.074767 grams

Idon’t know what the answer is i wish i could