What volume will 145 g of butane occupy at 745 torr and 35 ∘c?

First let us compute for the number of moles of butane (molar mass = 58.12 g/mol)

number of moles = 145 g / (58.12 g/mol) = 2.49 mol

We  use the ideal gas equation to calculate the volume:

 V = n R T / P

V = 2.49 mol * 62.36367 L torr / mol K * 308.15 K / 745 torr

V = 64.35 L

56 moles of   lieter in chemistry

level 4 to level 2 : ))