Determine the enthalpy for this reaction: mgcl2(s)+2naoh(aq)→mg(oh)2(s)+2nacl (aq) express your answer in kilojoules per mole to one decimal place.

Given reaction:

MgCl2(s) + 2NaOH(aq) → Mg(OH)2(s) + 2NaCl(aq)

Formula:

ΔH°rxn = ∑nΔH°f(products) - ∑nΔH°f(reactants)

           = [ΔH°f(Mg(OH)2) + 2ΔH°f(NaCl)] -[ΔH°f(Mg(Cl)2 + 2ΔH°f(NaOH)]

           = [-924.7+2(-407.2)] - [-641.6+2(-470.1)] = -157.3 kJ/mol

Ans: Enthalpy for the reaction is -157.3 kJ/mol

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.  

the role of the microscope world in creating new materials .