Astudent finds that 12.34 ml of a naoh solution is needed to neutralize 0.5678 g of potassium hydrogen phthalate (khc8h4o4). what is the concentration of the naoh solution? express your answer in mol/l.

1. we want molarity,but first we need to find out moles. moles KHP = 0.5678g/204.2g = 2.780X10^-3 mol KHP 2. use stoich to detemine moles of naoh 1 mol KHP= 1 mol NAOH so there are 2.780x10^-3mol NAOH M= (2.780X10^-3mol NAOH/12.34mL) x (1000L/1L) M= 0.2254 mol/l