Carbon dioxide and water are produced when pentane (c5h12) reacts with oxygen. what is the balanced equation for this reaction? c5h12(g) + o2(g) → co2(g) + h2o(g) c5h12(g) + o2(g) → 5co2(g) + h2o(g) c5h12(g) +8o2(g) → 5co2(g) + 6h2o(g) 5co2(g) + 6h2o(g) → c5h12(g) + 8o2(g) c5h12(g) +5o2(g) → 5co2(g) + 6h2(g) ch2(g) +o2(g) → co2(g) + h2(g)

C5H12 + 8O2--->5CO2 + 6H2O

C₅H₁₂(g) +8O₂(g) → 5CO₂(g) + 6H₂O(g)

Explanation:

I recommend to follow the whole process from the reactants to the products.

1) Word equation:

pentane + oxygen → carbon dioxide + water

This is a combustion (oxidation) reaction of an hydrocarbon.

2)  Chemical equation:

C₅H₁₂(g) +O₂(g) → CO₂(g) + H₂O(g

3) As per the mass conservation law,  in a chemical reaction, the number of each kind of atoms in the reactants must be equal to the number of the same kind of atoms in the products, which implies that you must add the coefficients required to balance the two sides of the reaction.

Start balancing the C atoms by adding a coefficient (5) in front of CO₂:

       C₅H₁₂(g) +O₂(g) → 5CO₂(g) + H₂O(g)

Continue adding a coefficient (6) in front of H₂O to balance the H atoms:

       C₅H₁₂(g) + O₂(g) → 5CO₂(g) + 6H₂O(g)

So far, there are 5 atoms of C on each side, and 12 atoms of H on each side. So, count the O atoms: there are 2 on the left side and 5×2 + 6 = 16 atomos of O on the right side. Then, you must add a coefficient (8) in front of O₂ on the left side to balance this atom, leading to this final result:

       C₅H₁₂(g) +8O₂(g) → 5CO₂(g) + 6H₂O(g)

Finally, there are 5 atoms of C, 16 atoms of O, and 12 atoms of H on each side, and the equation is balanced.

The answer is !

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