(a) starting with solid sucrose, c12h22o11, describe how you would prepare 250 ml of a 0.250 m sucrose solution. (b) de- scribe how you would

a. We first calculate the moles of sucrose needed

moles sucrose = 0.250 M * 0.25 L

moles sucrose = 0.0625 mol

The molar mass of sucrose 342.3 g/mol, so the mass of sucrose needed is:

mass sucrose = 0.0625 mol * 342.3 g/mol

mass sucrose = 21.4 grams

So simply dissolved about 21.4 grams of sucrose in 250 mL solution.

b. We use the formula:

M1 V1 = M2 V2

1.50 M * V1 = 0.100 M * 0.350 L

V1 = 0.0233 L = 23.3 mL

So simply take 23.3 mL of solution from 1.50 M then dilute it with water until 350 mL to make 0.100 M.