Calculate the mass of silver chloride in grams required to make 5.8 g of silver plating.

Silver chloride is simply AgCl while silver is Ag so we see that there is one mole to one mole correspondence. First calculate the moles of Ag:

moles Ag = 5.8 g / ( 107.87 g/mol)

moles Ag = 0.0538 mol

Then the mass of AgCl required:

mass AgCl = 0.0538 mol * 143.32 g/mol

mass AgCl = 7.71 grams

it would be a gas formation

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.