Bacteria and viruses are inactivated by temperatures above 139 ∘c in an autoclave. an autoclave contains steam at 1.00 atm and 100 ∘c. at what pressure, in atmospheres, will the temperature of the steam in the autoclave reach 139 ∘c, if n and v do not change?

To answer this question, we will use pressure law which states that:
"At constant volume of a fixed mass of gas, the pressure of the gas is directly proportional to the temperature"

This means that:
Pi / Ti = Pf / Tf where:
Pi is the initial pressure = 1 atm
Ti is the initial temperature = 100 + 273 = 373 degree kelvin
Pf is the final pressure that we want to calculate
Tf is the final temperature = 139 + 273 = 412 degree kelvin

Substitute in the equation with the givens to calculate the pressure as follows:
1 / 373 = Pf / 412
Pf = (1/373) * 412 = 1.104557641 atm

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer