If a solution at ph 5 undergoes a 1000-fold increase in [oh-], what is the resulting ph?

We have that the  the resulting pH is mathematically given as

PH=2

From the question we are told

If a solution at pH 5 undergoes a 1000-fold increase in [OH-], what is the resulting pH?

Generally the equation for the solution is  is mathematically given as

5=-log[H+]

H+=10e-5*1e3

H+=10e-2

Therefore

-log[H+]=-log[10e-2]

PH=2

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