How many moles of caco3 would have to be decomposed to produce 129 grams of cao?

2.3 moles CaCO₃

Explanation:Decomposition reaction is a type of reaction where a compound is broken down to smaller compounds or individual elements.For example, decomposition of calcium carbonate to yield calcium oxide and carbon dioxide.

That is;

CaCO₃(s) → CaO(s) +CO₂(g)

From the question, 129 grams of CaO were formed

We are required to calculate the number of moles of CaO used.

This can be done in the following steps;

Step 1: Moles of CaO produced

The number of moles is calculated by dividing mass by the molar mass of a compound.

Molar mass of CaO is 56.0774 g/mol

Therefore;

Moles of CaO = 129 g ÷ 56.0774 g/mol

                       = 2.3 moles

Step 2: Moles of CaCO₃ decomposed

From the equation 1 mole of CaCO₃ decomposes to yield 1 mole of CaO

Therefore;

For 2.3 moles of CaO to be produced then 2.3 moles of CaCO₃ would be decomposed.

Therefore;

The moles of CaCO₃ decomposed is 2.3 moles

Inot sure what it is i sorry : ((

For cyclohexane compounds drawn in a chair conformation:   -axial bonds are vertical  -equatorial bonds are parallel to two bonds within the ring.  thus, as i assume the chair conformation is drawn:   -the x group is in an axial position, as are the five other vertical bonds.  -three axial bonds are on the top face of the ring  -the other three axial bonds are on the bottom face  the position of the second substituent on each ring carbon is equatorial.  gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other.  drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1.  click this link and watch some academic videos that may you more understand the topic